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IBM C9050-042 : Developing with IBM Enterprise PL/I
- Exam Code: C9050-042
- Exam Name: Developing with IBM Enterprise PL/I
- Updated: Sep 22, 2026 Q&As: 140 Questions and Answers
About IBM C9050-042 Exam
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IBM C9050-042 Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Performance and Optimization | 15% | - I/O and processing performance - Memory and storage efficiency - Compiler options and runtime tuning |
| Topic 2: Advanced PL/I Concepts | 25% | - Object-oriented features in PL/I - Error and exception handling - Structures and records - Pointers and dynamic memory allocation - Strings and arrays |
| Topic 3: Debugging, Testing and Maintenance | 15% | - Unit testing and code validation - Debugging techniques and tools - Compilation and listing analysis |
| Topic 4: File Processing and Database Connectivity | 20% | - Sequential and VSAM file processing - Database connectivity and SQL integration - Data manipulation and transaction control |
| Topic 5: PL/I Language Fundamentals | 25% | - Procedures and functions - Variables, constants, and expressions - Control structures - I/O operations and file handling - Syntax and data types |
IBM Developing with IBM Enterprise PL/I Sample Questions:
Question #1
Which of the following is LEAST likely to be performed by a batch program?
- A. User interaction
- B. Sorting
- C. Production of pay checks
- D. Sequential file processing
Correct Answer: A 🗳️
Question #2
In which of the following groups of compiler options could all the options specified cause the compiler to
generate code which requires more time at execution?
- A. APCH(5),BIFPREC(31),NOTESTMTUNE(5),NOSERVICE
- B. OPTIMIZE(0),NOREDUCE,PIREFIX(SIZE,SUBSCRIPTRANGE)
- C. OPTIMIZE(2),DEFAULT(REORDER,NOLAXDCL,NOLAXCTL),STORAGE,MMTEMP(1000)
- D. ATTRIBUTES(FULL),XREF(FULL),DEFAULT(EVENDEC,DUMMY(UNALIGNED)),OFFSET
Correct Answer: B 🗳️
Question #3
The following structure is used when writing a file on Intel architecture which is sent to the mainframe:
DCL 1 A,
2 B FIXED BIN(31),
2 C CHAR (100) VAR,
2 D FIXED BIN(31);
How must this structure be declared on the mainframe if the file is to be read correctly?
- A. DCL1 A,
2 B FIXED BIN(31) BIGENDIAN, 2 C CHAR (100) VAR BIGENDIAN, 2 D CHAR (10); - B. D CL 1 A,
2 B FIXED BIN(31) BIGENDIAN,
2 C CHAR (100) VAR,
2 D CHAR (10); - C. DCL1 A,
2 B FIXED BIN(31) LITTLEENDIAN,
2 C CHAR (100) VAR LITTLEENDIAN,
2 D CHAR (10); - D. DCL1 A,
2 B FIXED BIN(31) LITTLEENDIAN,
2 C CHAR (100) VAR,
2 D CHAR (10);
Correct Answer: C 🗳️
Question #4
In the following example how many lines, if any, will be printed?
GRAPH: PROC OPTIONS(MAIN);
DCL I FIXED BIN(31);
DCL POINTS FIXED BIN(31);
CALL INIT_POINTS;
DO I = 1 TO 100;
GET LIST(POINTS);
CALL PLOT_NEXT(POINTS);
END;
INIT_POINTS: PROC;
DCL I FIXED BIN(31);
DCL POINTS(1000) FIXED BIN (31);
DCL BAR CHAR (100) INIT((100)'*') STATIC;
DO I 1 TO 10;
POINTS(I) = I;
PUT SKIP LIST (POINTS(I),SUBSTR(BAR,1,I));
END;
RETURN;
PLOT_NEXT: ENTRY(I);
POINTS(I) = I;
PUT SKIP LIST(POINTS(I),SUBSTR(BAR,1 I));
END;
END GRAPH;
- A. 110
- B. 10
- C. 100
- D. It is unpredictable as the program will fail.
Correct Answer: D 🗳️
Question #5
Given the following code, what will happen?
DCL(K, L) FIXED DEC (1);
K= 1;
L = 2;
PUT SKIP LIST (12+K/L);
- A. The resulting value is 6.5.
- B. The output is 12.4999999999999.
- C. The program ends abnormally at runtime.
- D. The output is 12.5.
Correct Answer: C 🗳️
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